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a = [3, 4, 5, 6]b = [1, 4, 6, 8]#以下几种方法是等效的results_1= [x for x in b if x in set(a)]print('results_1:',results_1)results_2= list(set(a) & set(b))print('results_2:',results_2)results_3= list(set(a).intersection(b))print('results_3:',results_3)results_4 = list((set(a).union(set(b)))^(set(a)^set(b))) #不推荐,太麻烦print('results_4:',results_4)
结果:
a = [3, 4, 5, 6]b = [1, 4, 6, 8]results_1= list(set(a).union(set(b)))print('results_1:',results_1)results_2= list(set(a) | set(b))print('results_2:',results_2)
输出:
a = [3, 4, 5, 6]b = [1, 4, 6, 8]#求b相对于a的补集,元素属于a但不属于bresults_1= [ i for i in a if i not in b ]print('results_1:',results_1)results_2= list(set(a).difference(set(b)))print('results_2:',results_2)results_3= set(a)-set(b)print('results_3:',results_3)
输出:
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